Question

solve it yr............

Answer 1

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Answer 2

HELLO DEAR,

X = (√3 + 1)/2

∴[ on SQUARING both side]

We get,

x² = (√3 + 1)²/2²

⇒ x² = (3 + 1 + 2√3)/4

⇒ x² = (4 + 2√3)/4

⇒ x² = 2(2 + √3)/4

⇒ x² = (2 + √3)/2

now,

4x³ + 2x² - 8x + 7

⇒ 2x²(2x + 1 ) - 8x + 7

⇒ 2×(2 + √3)/2 [ ( 2×(√3 + 1)/2 + 1 ] - 8(√3 + 1)/2 + 7

∴ [ x² = (2 + √3)/2 & x = (1 + √3)/2]

⇒ (2 + √3) (√3 + 2 ) - 4√3 - 4 + 7

⇒ 4 + 3 + 4√3 - 4√3 - 4 + 7

⇒ 7 + 3

⇒ 10.

I HOPE ITS HELP YOU DEAR,
THANKS