solve itt....................
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SOLUTION:
given that:-
AB = 3cm = AE = 3cm ,
BC = (x - y) ,
CD = (x + y) ,
BE = 5cm
in the fig, BE || CD , BC || DE , and , BC ⊥ CD,
thus, BCDE is rectangle,
hence, CD = BE = 5cm , BC = DE = (x - y)
(x + y) = 5----------( 1 )
now,
perimeter of ABCDE = AB + BC + CD + DE + AE
now, put the values of them
we get,
21 = 3 + (x - y) + (x + y) + (x - y) + 3
[ perimeter = 21 (given), ]
=> 21 = 6 + 2(x - y) + (5) ----------------from --( 1 )
=> 21 - 11 = 2(x - y)
=> 10/2 = (x - y)
=> (x - y) = 5 ----------( 2 )
from------( 1 ) & ------( 2 )
x + y = 5
x - y = 5
—————
2x = 10
x = 5 ---[ put in ---( 1 ) ]
we get,
x + y = 5
5 + y = 5
y = 5 - 5
y = 0 , x = 5
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