Question

Solve
ix²-3x-2i=0 by formula method​

Answer 1

Solve ix²-3x-2i=0 by formula method

$i {x}^{2} - 3x - 2i = 0$

$or \: {x}^{2} + 3ix - 2 - 0 = - 2 - 0$

$divide \: by \: 1$

$x = - \frac{ - 3 + \sqrt{ - 9 + 4.1.2} }{2.1}$

$x = \frac{ - 3i + \sqrt{ - 1} }{2}$

$x = \frac{ - 3i + i}{2}$

$x = - 1 \: or \: - 2i$

$bts ❤ exo$

Answer 2

$\huge\underline{\pink{\bf{Question:-}}}$

ix²-3x-2i=0 by formula method

$\huge{\boxed{\mathtt{\red{SoLuTiOn:-}}}}$

x = i or x = -2i

$\huge\bf\underline{\underline{\pink{**B} \orange{e}\blue{c}\red{o}\green{u}\purple{se**}}}$

ix²-3x-2i=0

or x² + 3ix - 2 = 0 ( Device by i )

or

$x = \ \frac{ - 3i + \sqrt{ - 9 \: + 4.1.2} }{2.1} = \ - \frac{ - 3i + \sqrt{ - 1} }{2} = \ \frac{ - 3i + i}{2}$

➡️x = -i or x = -2i