Solve k:
(k^2+k/2) + 4k = 2550
adityakumar8jjhu:
hi
Answers
Answered by
19
Since the above equation has equal roots
Hence
B
2
−4AC=0
Hence
4(2k−3)
2
−4(5k−6)(k−2)=0
4k
2
−12k+9−(5k
2
−16k+12)=0
−k
2
+4k−3=0
Or
k
2
−4k+3=0
(k−3)(k−1)=0y
Hence
k=3 and k=1.
I think it will be helpful to you my friend
#Khushu☺️
Answered by
0
Answer:
k= 3 and k = 1
Step-by-step explanation:
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