Question

solve kar do yaar please please please ​

Answer 1

Answer:

In △ADC,

S is the mid-point of AD and R is the mid-point of CD

∴SR∥AC and SR= 1/2 AC....(1)

since line segments joining the mid-points of two sides of a triangle is parallel to the third side and is half of it.

In △ABC,

P is the mid-point of AB and Q is the mid-point of BC

∴PQ∥AC and PQ= 1/2 AC ....(2)

since line segments joining the mid-points of two sides of a triangle is parallel to the third side and is half of it.

From (1) and (2)

⇒PQ=SR and PQ∥SR

So, in PQRS, one pair of opposite sides are parallel and equal.

Hence PQRS is a parallelogram.

PR and SR are the diagonals of parallelogram PQRS

So, OP=OR and OQ=OS (Diagonals of a parallelogram bisect each other)

Hence proved.