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kal board exam paper hai yar
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answer=20, 35.for solution see image.
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let the ratio of the lengths be 4x and 7x.
height = 14m
area of trapezium = 385 m square
1/2 * ( sum of all parallel sides ) * h = 385
1/2 * ( 4x + 7x ) * 14 = 385
1/2 * 11x * 14 = 385
11x * 7 = 385
11x = 385/7
11x = 55
x = 55/11
x = 5
4x = 4 * 5 = 20m
7x = 7 *5 = 35m
So, the length of the parallel sides are 20m and 35m.
height = 14m
area of trapezium = 385 m square
1/2 * ( sum of all parallel sides ) * h = 385
1/2 * ( 4x + 7x ) * 14 = 385
1/2 * 11x * 14 = 385
11x * 7 = 385
11x = 385/7
11x = 55
x = 55/11
x = 5
4x = 4 * 5 = 20m
7x = 7 *5 = 35m
So, the length of the parallel sides are 20m and 35m.
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