Question

Solve kari do ne please ​

Answer 1

Answer:

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Answer 2

Given:

$\huge{\rm \frac{\sin^2 63\degree + \sin^2 27\degree}{\cos^2 17\degree + cos^2 73\degree}}$

Solution:

We have,

$\therefore \rm \frac{\sin^2 63\degree + \sin^2 27\degree}{\cos^2 17\degree + cos^2 73\degree}$

As, 63 + 27 = 90

Also, 63 = 90 - 27

Simillarly, 17 + 73 = 90

Also, 17 = 90 - 73

Replacing values,

$\implies \rm \frac{[\sin(90\degree - 27\degree)]^2 + \sin^2 27\degree}{[\cos(90\degree - 73\degree)]^2 + \cos^2 73\degree}$

As we know that,

$\it \sin(90\degree - A) = \cos A$

and also,

$\it \cos(90\degree - A) = \sin A$

So, we get

$\implies \rm \frac{[\cos 27\degree]^2 + \sin^2 27\degree}{[\sin 73\degree]^2 + \cos^2 73\degree}$

$\implies \rm \frac{\cos^2 27\degree + \sin^2 27\degree}{\sin^2 73\degree + cos^2 73\degree}$

Also, we know that,

$\it \cos^2 A + \sin^2 A = 1 \\ \it or, \: \sin^2 A + \cos^2 A = 1$

So, we get

$\implies \rm \frac{1}{1}$

$\texttt{Ans.} \rm \bf \red{1}$