Question

solve karo jaldi..quick,dam h to,no spam​

Answer 1

Hii

you are welcome in my answer

t =( x^2 - 1)^1/2

squiering on both side

t^2 = x^2 - 1

on differentiating with respect to X we get

2x dx/dt = 2t

v = dx/dt = t/x

again diffrenciating with respect to t

d^2x/dt^2 * x + dx/dt * dx/dt = 1

a= d^2x/dt^2= 1 - t^2/x^2

a = d^2x/dt^2 = 1 - (x^2 +1)/x^2

a = 1/x^2

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Hope it may helps you