Question

Solve karo yrr........

one que

with steps​

Answer 1

Let first number =x

then the other number = 15−x

According to the question

x1+15−x1=103

10(15−x+x)=3(x(15−x))

150=45x−3x2

3x2−45x+150=0

x2−15x+50=0

x2−10x−5x+50=0

(x−10)(x−5)=0

x=10,x=5

Answer 2

Answe:

x=5 and y=10

Step-by-step explanation:

Let the 2 no.s be x and y .

x+y=15 (eqn .1)

1/x+1/y=3/10(eqn.2)

From eqn 1;

x=15-y

Putting eqn 3 in eqn 2:

1/15-y +1/y=3/10

y+15-y/y(15-y)=3/10

15/15y-y^2=3/10

Then,we get a quadratic eqn:y^2-15y+50=0(Sum= -15,Product =50)

The eqn becomes y(y-10)+5(y-10)=0

Putting y+5=0

Then y= -5(not possible)

Putting y-10=0

Then y=10

Then put the value of y =10 in any of the above eqn we get x=5

Therefore:x=5 and y=10 are the no.s.

HOPE THIS IS HELPFUL.IF YES THEN GIVE ME A STAR.