Solve kr ke de do yaar
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a)7m/s
b)2m/s.sq
Explanation:
a) Velcoity at 2.5 seconds is 7m/s
b) Acceleration = slope of velocity time graph
=(14−2)/(6−0)
=2m/s.sq.
c) Distance covered in last 4 seconds is the area under the curve for last 4 second
i.e.
Total distance covered in last 4 seconds
= area under ABCD
= area of ABED + area of BCE
=((6−0)×(6−2))+ (14−6)×(6−2)/2
=24+16
=40m
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