solve kro ise maths K aaryabhat.
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(2p+1)x²-(7p+2)x+(7p-3)=0
- A=(2p+1)
- B=(7p+2)
- C=(7p-3)
=>D=0
=>D=B²-4AC=0
=(7p+2)²-4×(2p+1)(7p-3)=0
=49p²+4+28p-56p²-4p+12 = 0
=7p²-24p-16=0
=7p(p-4)+4(p-4)=0
=(p-4)(7p+4)=0
=p=4& p=-4/7
Answer :-4
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i hope it will help uh.....
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