Question

Solve LHS=RHS.Anyone can do it.

Answer 1

here is the answer
hope it helps : )

Answer 2

$( {sin}^{2} \alpha \div {cos}^{2} \alpha ) + 1 = ( {sin}^{2} \alpha + {cos}^{2} \alpha ) \div {cos}^{2} \alpha = 1 \div {cos}^{2} \alpha$
multiplying and dividing by
${sin}^{2} \alpha$
then,
$( \frac{ {sin}^{2} \alpha }{ {cos}^{2} \alpha } ) \times ( \frac{1}{ {sin}^{2} \alpha } ) = \frac{ {tan}^{2} \alpha }{ {sin}^{2} \alpha }$