Question

Solve lim x-> 0 [ sinx/cosx]​

Answer 1

Step-by-step explanation:

alue of x\quad =\quad\frac { -19 }{ 3 }=

3

−19

Given:

\frac{(2 x + 1)}{(3 x - 2)}=\frac{5}{9}

(3x−2)

(2x+1)

=

9

5

To find:

Value of x

Solution:

\frac{(2 x + 1)}{(3 x - 2)}=\frac{5}{9}

(3x−2)

(2x+1)

=

9

5

Cross multiplying,

We get,

9(2 x + 1)\quad =\quad 5(3 x - 2)9(2x+1)=5(3x−2)

18x + 9 = 15x - 10

18x - 15x = -10 - 9

3x\quad =\quad -193x=−19

x\quad =\quad \frac { -19 }{ 3 }