Math, asked by udituniquerit, 1 year ago

Solve
Limit(x-1)
(x^3-3x+1)/(x-1)

Answers

Answered by jobanputraronil
0
apply  le hospital rule as it tends to infinity by putting x = 1 ther for taking derivative of abov and below individual 

we get 3x^2-3/1
now put lmits x tends to 1 therfor ans is 3*1^2-3=0

jobanputraronil: plz marl as best
Answered by Anonymous
0
Limit does not exist, because as x→1-, the expression is positive.
And as x→1+, the expression is negative.
Apply L'Hospital's rule only when the function is in indeterminate form such as \frac{0}{0} or \frac{\± \infty }{\± \infty}  .
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