Question

solve Limits (class 11) .... Fast don't cheat pls​

Answer 1

$\displaystyle\\\lim_{x\to 0}\left(\dfrac{3^{2x}-2^{3x}}{x}\right)=\\\\\lim_{x\to 0}\left(\dfrac{9^{x}-8^{x}}{x}\right)=\\\\\lim_{x\to 0}\left(\dfrac{(9^{x}-8^{x})'}{x'}\right)=\\\\\lim_{x\to 0}\left(\dfrac{9^ x\ln 9-8^ x\ln 8}{1}\right)=\\\\\lim_{x\to 0}\left(9^ x\ln 9-8^ x\ln 8\right)=\\\\9^ 0\ln 9-8^ 0\ln 8=\ln 9-\ln 8=\ln\dfrac{9}{8}$

Answer 2

Answer:

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