Question

Solve linear equation by cross multification method
8x+5y=11
3x-4y=10​

Answer 1

Answer:

there I hope there is no silly mistake and it helps

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Answer 2

let equation 1st ×-4

-32x-20y=44

equation 2nd×5

15x-20y=50

so by equating coefficient method

adding both equation

-32x-20y=44

15x-20y=50

-47x+00=94

so -47x=94

X=-2

put x=-2 in eqn 2nd

3x-4y=10

3×-2-4y=10

-6-4y=10

-4y=10+6

-4y=16

y=-4

so solutions of equations r x=-2 and y =-4