Solve linear equation by trial and error method .
-12k+3k=-18
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Since at k= 2, LHS = RHS
Hence, k = 2 is the solution of the given equation.
Check :- let us substitute k=2 in the given equation, we get
LHS = -12×2+3×2 = -18
RHS = -18
hence, k = 2 is the required solution
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