Question

Solve:
log(1/2)+log(2/3)+....+log(99/100)

Answer 1

SOLUTION :-

We Know That,

log a + log b= log (ab)

so for this expanson we can write it as

log(1/2 × 2/3 × 3/4 × 4/5 × .............98/99 × 99/100)

here we can see many terms will cancel each other only remaining withlog(1/100)

= -log(100)

= -2