Solve log (1+x) + log (1-x)
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A logarithmic property states that:
log(a) + log(b) = log(ab) provided that base of both the logarithms is same.
Thus,
log(1+x) + log(1-x) = log{(1+x)(1-x)}
= log(1-x^2)
Hence,the answer is log(1-x^2)
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