solve log 2 x square - 5 x + 14 is equal to 3
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I got the job done today I will see you guys at home tomorrow morning and I can get the
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Here we go,

Now all you gotta do is solve this quadratic equation,

So one of the values must be 0 to get RHS = 0.
The roots we get then are,

and

Since logarithms aren't defined for -ve values.
The positive value is taken into consideration and hence x = 17.
Now all you gotta do is solve this quadratic equation,
So one of the values must be 0 to get RHS = 0.
The roots we get then are,
and
Since logarithms aren't defined for -ve values.
The positive value is taken into consideration and hence x = 17.
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