Math, asked by rohan8731, 20 days ago


Solve : log(2x + 1) + log(3x – 1) = 0.

Answers

Answered by sonalminz
18

Answer:

I hope this will help you

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Answered by presentmoment
0

x=0.5

Step-by-step explanation:

log(2x + 1) + log(3x – 1) = 0

log(2x + 1) = -log(3x – 1)

log(2x+1)= log(\frac{1}{3x-1})

taking antilog on both sides,

2x+1= 1/3x-1

On solving this,

we get

x=1/2

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