Question

Solve log (3y-1)=log(2y+1)-log4

Answer 1

Answer:

y = 3/10

Step-by-step explanation:

log (3y-1) = log(2y+1) - log4

$log(3y - 1) = log\frac{(2y+1)}{4}$

$3y - 1 = \frac{2y + 1}{4}$

(3y - 1 ) × 4 = 2y - 1

12y - 4 = 2y - 1

12y - 2y = -1 +4

10y = 3

y = 3/10