Question

solve log{4-5log32(x+3)}=0​

Answer 1

Given:

$\rm \log((4-5)\log_{32}(x + 3)) =0$

Solution:

$\rm \therefore \log((4-5)\log_{32}(x + 3)) =0 \\ \\ \implies \rm \log(-3.52(x + 3)) = 0 \\ \\ \rm \implies \rm \log(-3.52x - 10.57) = 0 \\ \\ \rm \implies \log(-3.52x) - \log(10.57) = 0 \\ \\ \rm \implies 0.54x - 1.02 = 0 \\ \\ \rm \implies 0.54x = 1.02 \\ \\ \rm \implies x = \frac{1.02}{0.54} \\ \\ \rm \implies \bf \red{ x = 1.88}$