Question

solve log (x+5)base 2-log 2(x-1)base 2=5 ​

Answer 1

Answer:

$log_{2}(x + 5) - log_{2}(2x - 2) = 5 log_{2}(2) = log_{2}( {2}^{5} ) = log_{2}(32)$

$log_{2}( \frac{x + 5}{2x - 2} ) = log_{2}(32)$

$\frac{x + 5}{2x - 2} = 32$

$x + 5 = 64x - 64$

$64x - x = 5 + 64$

$63x = 69$

$x = \frac{69}{63} = \frac{23}{21} \: ans.$

Answer 2

Answer:

same as above solution. nice work