Chemistry, asked by yashas3067, 10 months ago

solve log x/log 3=log 25/log 9​

Answers

Answered by pandeysakshi200310
11

Answer:

log x/log5 = log9/log(1/3)

logx/log5=3log2/(-log3)

log x = -2log5

log x=log1/25

therefore; x=1/25

Explanation:

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Answered by Swati3101
0

Answer:

The value of x is \bold{5}.

Explanation:

Given that \frac{log x}{log 3} =\frac{log 25 }{log 9}

Now we rewrite the given equation as

\frac{log x}{log 3} =\frac{log 5^2 }{log 3^2}

Now apply the logarithm property log x^a=alog x in the above equation, we get

\frac{log x}{log 3} =\frac{2 log 5 }{2 log 3}

By canceling the like terms we get

logx=log 5

By canceling log on both sides, we have

x=5

Hence, The value of x is \bold{5}.

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