Question

Solve log, (x²+x) - log,(x + 1) = 2.​

Answer 1

Answer:

$x=100$

Step-by-step explanation:

$log(x^2+x)-log(x+1)=2$          

$log(\frac{x^2+x}{x+1} )=2$                                ∵ $log(a)-log(b)=log(\frac{a}{b})$

$log(\frac{x(x+1)}{x+1} )=2$                             ∵ $x\neq -1$

$log(x)=2$

taking anti-log

$x=10^2$

$x=100$