Question

Solve log(xy/z)+log(yz/x)log(zx/y) if x=1

Answer 1

Step-by-step explanation:

logxy-logz+(logyz-logx)log(zx-logy)

as x=1

logy-logz+(logyz-log1)(logz-logy)

as log1=o

logy-logz+(logyz) (logz-logy)

logy-logz+(logy+logz) (logz-logy)

logy-logz+log²z-log²y

logy-logz+2logz-2logy

logz-logy

hopes it may help you

Answer 2

The answer is ㏒(yz)

Given: x = 1

To find:  ㏒$(\frac{xy}{z} )$ + ㏒ $(\frac{yz}{x} )$ ㏒ $(\frac{zx}{y} )$  

Solution: Given x = 1, substitute x = 1 in

⇒ ㏒$(\frac{y}{z} )$ + ㏒ $(yz)$ ㏒ $(\frac{z}{y} )$

As we know  ㏒(a/b) = ㏒ (a) – ㏒ (b)  and ㏒ (ab) = ㏒ a + ㏒ b

⇒ ㏒ y - ㏒ z +  ㏒ $(yz)$ + ㏒ $(\frac{z}{y} )$

⇒ ㏒ y - ㏒ z +  ㏒ y + ㏒ z  + ㏒ z - ㏒ y  

⇒ ㏒ y + ㏒ z  

⇒ ㏒(yz)

Therefore, the answer is ㏒(yz)

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