solve log2 (x+5)-log2(2x-1)=5
Answers
Answered by
3
Answer:
I found:
x
=
37
63
Explanation:
We can change the subtraction into a division of arguments and write:
log
2
(
x
+
5
2
x
−
1
)
=
5
then we use the definition of log to get rid of it and write:
x
+
5
2
x
−
1
=
2
5
x
+
5
2
x
−
1
=
32
rearrange:
x
+
5
=
64
x
−
32
and:
63
x
=
37
so:
x
=
37
63
Answered by
14
Answer:
Explanation:
We can change the subtraction into a division of arguments and write:
log
2
(
x
+
5
2
x
−
1
)
=
5
then we use the definition of log to get rid of it and write:
x
+
5
2
x
−
1
=
2
5
x
+
5
2
x
−
1
=
32
rearrange:
x
+
5
=
64
x
−
32
and:
63
x
=
37
so:
x
=
37
63
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