Question

Solve log2 x + log2 (x + 1) = 1​

Answer 1

Answer:

x=0,(-1)

Explanation:

log2 x + log2 (x+1) = 1

log2 x(x+1)=1

log2 (x(x+1))=1

since (log2 x(x+1)=1) means (log2^0) = x(x+1)

therefore:-

x(x+1)=0

it has two solutions

1) x=0

2)x+1=0

x=(-1)