Question

Solve log2 x + log2 (x - 1) = 1​

Answer 1

Formula

logm + logn = logmn

Applying Formula

log2[ ( x )( x - 1 ) ] = 1

x( x - 1 ) = 2

x² - x - 2 = 0

x² - 2x + x - 2 = 0

x( x - 2 ) + 1( x - 2 ) = 0

( x - 2 )( x + 1 ) = 0

x = -1,2

x = -1 will not be answer as we can't take negative values in log.

Answer

So, answer is 2 only.

Thank you.