Solve log2 x + log2 (x - 1) = 1
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Formula
logm + logn = logmn
Applying Formula
log2[ ( x )( x - 1 ) ] = 1
x( x - 1 ) = 2
x² - x - 2 = 0
x² - 2x + x - 2 = 0
x( x - 2 ) + 1( x - 2 ) = 0
( x - 2 )( x + 1 ) = 0
x = -1,2
x = -1 will not be answer as we can't take negative values in log.
Answer
So, answer is 2 only.
Thank you.
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