solve loga x+log4x+log2x =1
Answers
Answered by
1
Answer:
64
Step-by-step explanation:
log8x+log4x+log2x=11
or, log23x+log22x+log2x=11
or, 31log2x+21log2x+log2x=11
or, 611log2x=11
or, log2x=6
or, x=26
or, x=64.
Similar questions