solve logbase3 x =2
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Answered by
1
Rewrite
log
3
(
3
x
−
2
)
=
2
log3(3x-2)=2 in exponential form using the definition of a logarithm. If
x
x and
b
b are positive real numbers and
b
b
≠
≠
1
1, then
log
b
(
x
)
=
y
logb(x)=y is equivalent to
b
y
=
x
by=x.
3
2
=
3
x
−
2
32=3x-2
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