Question

solve:
m(2 m-3)= 2m²+66​

Answer 1

$= > m(2m - 3) = 2 {m}^{2} + 66$

$= > 2 {m}^{2} - 3m = 2 {m}^{2} + 66$

On cancelling 2m² from both sides,

$= > - 3m = 66$

$= > m = \frac{66}{ - 3}$

$= > m = - 22$

Answer 2

Given:

$m(2m-3) = 2m^{2} +66$

To Find:

Find the value of m from the given equation.

Solution:

Given equation is $m(2m-3) = 2m^{2} +66$

Now, $m(2m-3) = 2m^{2} +66$

or, $2m^{2}-3m = 2m^{2}+ 66$

or, $-3m = 66$

Therefore, $m = - 22$