Question

Solve m² +6m-27=0
it simple can anyone make this ​

Answer 1

Answer:

The first term is,  m2  its coefficient is  1 .

The middle term is,  -6m  its coefficient is  -6 .

The last term, "the constant", is  -27 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -27 = -27 

Step-2 : Find two factors of  -27  whose sum equals the coefficient of the middle term, which is   -6 .

     -27   +   1   =   -26     -9   +   3   =   -6   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  3 

                     m2 - 9m + 3m - 27

Step-4 : Add up the first 2 terms, pulling out like factors :

                    m • (m-9)

              Add up the last 2 terms, pulling out common factors :

                    3 • (m-9)

Step-5 : Add up the four terms of step 4 :

                    (m+3)  •  (m-9)

             Which is the desired factorization

Answer 2

m² +6m-27=0

on transposing the terms

m² + 6m = 27

${m}^{2} + m = \huge \frac{27}{6} = \frac{9}{2}$

$m + m = \huge \sqrt{ \frac{9}{2} }$

$2m = \huge \sqrt{ \frac{9}{2} }$

$\implies \: m = \huge\sqrt{ \frac{9}{2 \times 2} } = \sqrt{ \frac{9}{4} }$

$\boxed{m = \huge \frac{3}{2} }$

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