Question

SOLVE MATH for A and B (a+1)²+b²=4a+3(2b-3)

Answer 1

Answer:

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Step-by-step explanation:

View this expression as a quadratic in variable [math]a[/math].

View this expression as a quadratic in variable [math]a[/math].So you can rewrite this as [math]a^2-4a-(b^2-2b-3)[/math]

View this expression as a quadratic in variable [math]a[/math].So you can rewrite this as [math]a^2-4a-(b^2-2b-3)[/math]Now you can use the tools of solving quadratic to solve the problem. You can rewrite the factor as

View this expression as a quadratic in variable [math]a[/math].So you can rewrite this as [math]a^2-4a-(b^2-2b-3)[/math]Now you can use the tools of solving quadratic to solve the problem. You can rewrite the factor as[math]a+b-3=0[/math]

View this expression as a quadratic in variable [math]a[/math].So you can rewrite this as [math]a^2-4a-(b^2-2b-3)[/math]Now you can use the tools of solving quadratic to solve the problem. You can rewrite the factor as[math]a+b-3=0[/math][math]a=3-b[/math]

View this expression as a quadratic in variable [math]a[/math].So you can rewrite this as [math]a^2-4a-(b^2-2b-3)[/math]Now you can use the tools of solving quadratic to solve the problem. You can rewrite the factor as[math]a+b-3=0[/math][math]a=3-b[/math]Now you can apply synthetic division or any other type of polynomial division. Due to some reasons, I'm unable to show my workings here (unable to add it) but on dividing it, you get the other factor as