Question

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Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Given , quadratic polynomial is 4x²-4x+1.

To Find The Number of Zeros Put The polynomial Equals to 0 First.

→ 4x² - 4x + 1 = 0

Now, Splitting The Middle Term , we get,

→ 4x² - 2x - 2x + 1 = 0

→ 2x(2x - 1) - 1(2x - 1) = 0

→ (2x - 1)(2x - 1) = 0

Putting Both Equal to Zero now, we get,

→ 2x - 1 = 0

→ 2x = 1

→ x = (1/2)

Hence, Both Zeros of Quadratic Equation Are (1/2).

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Now, First Relation is :-

→ Sum of Zeros = - (coefficient of x) /(coefficient of x²)

Putting both values ,

→ (1/2 + 1/2) = -(-4)/4

→ 1 = 1 ✪✪ Hence Verified. ✪✪

Second Relation :-

→ Product Of Zeros = Constant Term / (coefficient of x²)

Putting both Values ,

→ (1/2) * (1/2) = (1) / (4)

→ 1/4 = 1/4 ✪✪ Hence Verified. ✪✪

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