Question

solve me this please​

Answer 1

Step-by-step explanation:

it will be by the process of middle term factorization

Answer 2

Answer:

1. $x^{2} + 3x - 28 = 0$

$x ^{2} - ( - 3)x + ( - 28) = 0$

compairing this with..

$x^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

$( \alpha + \beta ) = sum \: of \: the \: roots \: = - 3$

$\alpha \beta = product \: of \: the \: roots = - 28$

2.$3y ^{2} - y - 4 = 0$

$y ^{2} - \frac{y}{3} - \frac{4}{3} = 0$

$y ^{2} - (\frac{1}{3} ) y + \frac{ - 4}{3} = 0$

$\alpha + \beta = \frac{1}{3}$

$\alpha \beta = \frac{ - 4}{3}$