Math, asked by sarita50, 1 year ago

Solve:mr sharma divides ₹23550 among his childrens neha ,vishu and prasant in such a way that neha gets double of what vishu gets and vishu gets tripple of what prasant gets .how much each child gets?​

Answers

Answered by Anonymous
22

Let the share of Prashant in Rs 23550 = Rs x

Given that Vishnu's share is triple of Prashant

Therefore Vishnu's Share = Rs 3x

Also given that Neha's share is double of Vishnu

Therefore, Neha's share = Rs 2(3x) = Rs 6x

The sum of shares of these three people = Rs 23550

So, x + 3x + 6x = 23550

10x = 23550

x = 2355.

Finally,

Prashant's share = Rs 2355

Neha's share = Rs 6x = Rs 14130

Vishnu's share = Rs 3x = Rs 7065

Hope my answer helps you.

Answered by mitakaranmishra
11

Mr sharma divides rupees among his children = ₹ 23550

vishu get = 1. prasant get = 1

neha get = 2 vishu = 3

neha and vishu s ratio = 2:1. bishu : prasant = 3 : 1

2× 3 : 1 × 3

= 6 : 3

neha : vishu : prasant = 6 : 3 : 1

neha get = 23550 × 6 / 6+3+1 = 23550 × 6 / 10 = 14130

vishu get = 23550 × 3 / 6+3+1 = 23550 × 3 / 10 = 7065

prasant get = 23550 × 1 / 6+3+1 = 23550 × 1 / 10 =

2355

Therefore : - neha get = 14130

vishu get = 7065

prasant get = 2355

hope I can help you

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