SOLVE
mx-ny=m²+n²
x+y=2m
pls tell exams coming
Answers
Answered by
1
Answer:
given
mx-ny=m^2+n^2-------(1)
x+y=2m--------(2)
multiplying eq(1) by coefficient of x i.e.1 and eq(2) by coefficient of x i.e. m
we get,
mx-ny=m^2+n^2-------(3)
mx+my=2m^2----------(4)
subtracting eq(3) and (4) we get
-y(m+n)=m^2+n^2-2m^2
or -y(m+n)=-m^2+n^2
=-(m+n)(m-n)/(m+n)
y = m-n-----(5)
by putting the value of y in eq.(2) we get,
x=2m-(m-n)
hence solution is , x=m+n &y=m-n
Step-by-step explanation:
hope u have been understood
Similar questions