solve my above question...???
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❤Hola ❤
weight of diffraction pattern W is
proportional to lemda × D / a
therefore , W' / W = lemda ' / ( a/ 2) × a/ lemda
= 2 lemda' / lemda
= 2 × 600 / 400
= 3
W'= 3W
= 3y
✌✌
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hey mate here is ur answer☆☆☆☆☆
Explanation:
weight of diffraction pattern W is
proportional to lemda × D / a
therefore , W' / W = lemda ' / ( a/ 2) × a/ lemda
= 2 lemda' / lemda
= 2 × 600 / 400
= 3
W'= 3W
= 3y
☆☆☆
hope it helps u... mate
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