solve my question???????
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as you know in hint AB and AC is given
so we find
sintheta=p/h= BC/AC=4/2√13
cos theta=b/h=AB/AC=6/2√13
hope it helps
if it is correct
please add to brainlist answer
so we find
sintheta=p/h= BC/AC=4/2√13
cos theta=b/h=AB/AC=6/2√13
hope it helps
if it is correct
please add to brainlist answer
AyushSingh1111:
from where you got AB and AC
in hint last line
but answer is not correct
answer is given that. sin thita =2√13/13
sorry friend . your answer is correct
thanks
ok
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0
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