Question

solve (n-2)! / ( n-8)!​

Answer 1

Answer:

By definition of factorials

(n-7)! = (n-7)*(n-7-1)*(n-7-2)*…*1 = (n-7)*(n-8)*(n-9)*…*1

(n-8)! = (n-8)*(n-8-1)*(n-8-2)*…*1 = (n-8)*(n-9)*…*1

(n-7)! = (n-7)*(n-8)!

Likewise, 8! = 8*7!

Equating the two given expressions you have:

7!(n-7)! = 8!(n-8)!

Substituting for (n-7)! on the left side and 8! on the right side you have:

7!(n-7)(n-8)! = 8*7!(n-8)!

Dividing both sides by 7!(n-8)! You are left with

n – 7 = 8

Hence n = 15

Step-by-step explanation:

please make me brilliant