Math, asked by sharansss114, 1 year ago

solve n^2 plus 201n - 2700
with method
first correct answer will be marked as brainliest

Answers

Answered by mriganka2
0
First,you wrote a wrong question.
the question should be---
solve for n when n^2+201n-2700=0

you can use the quadratic formula to solve it.


n =  \frac{ - 201 + 3 \sqrt{5689} }{2}
or,,

n=  \frac{ - 201 - 3 \sqrt{5689} }{2}
for the first answer the approximate value of n is 12.63819

and for the second one the approximate value of n is -213.63819



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