Question

Solve :-

#need correct ans

Answer 1

$Given: \frac{3x + 1}{6} + \frac{2x - 3}{7} = \frac{x + 3}{8} + \frac{3x - 1}{14}$

LCM of 6,7,8,14 = 168.

$= \ \textgreater \ \frac{3x + 1}{6} * (168) + \frac{2x - 3}{7} * (168) = \frac{x + 3}{8} * (168) + \frac{3x - 1}{14} * (168)$

= > 28(3x + 1) + 24(2x - 3) = 21(x + 3) + 12(3x - 1)

= > 84x + 28 + 48x - 72 = 21x + 63 + 36x - 12

= > 132x - 44 = 57x + 51

= > 132x = 57x + 95

= > 75x = 95

= > x = 95/75

= > x = 19/15.



Hope this helps!

Answer 2

$\bold{\frac{3x + 1}{6} + \frac{2x - 3}{7} = \frac{x + 3}{8} + \frac{3x - 1}{14}}$



$\bold{\frac{7(3x + 1) + 6(2x - 3)}{42}=\frac{14(x + 3)+8(3x - 1)}{112}}$



$\bold{\frac{21x + 7 + 12x - 18}{42} = \frac{14x + 42 + 24x - 8}{112}}$



$\bold{\frac{33x - 11}{42} = \frac{38x + 34}{112}}$



$\bold{\frac{33x - 11}{3} = \frac{38x + 34}{8}}$



$\bold{264x - 88 = 114x + 102}$



$\bold{264x - 114x = 102 + 88}$



$\bold{150x = 190}$



$\bold{x = \frac{190}{150}}$



$\bold{x = \frac{19}{15}}$