solve no 3 in full process
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Given 78m - 143.
143 > 78.
(1) 143 = 78 * 1 + 65
The remainder is not equal to 0. use division algorithm to 78 and 65.
(2) 78 = 65 * 1 + 13
The remainder is not equal to 0. Use division algorithm to 65 and 13.
(3) 65 = 13 * 5 + 1
The remainder is 0.
Therefore the HCF of 78 and 143 = 13.
Now,
13 = 78 - 65 * 1
= 78 - (143 - 78) * 1
= 78 - 143 * 1 + 78 * 1
= 78(2) - 143.
Therefore the value of m = 2.
.
Hope this helps!
143 > 78.
(1) 143 = 78 * 1 + 65
The remainder is not equal to 0. use division algorithm to 78 and 65.
(2) 78 = 65 * 1 + 13
The remainder is not equal to 0. Use division algorithm to 65 and 13.
(3) 65 = 13 * 5 + 1
The remainder is 0.
Therefore the HCF of 78 and 143 = 13.
Now,
13 = 78 - 65 * 1
= 78 - (143 - 78) * 1
= 78 - 143 * 1 + 78 * 1
= 78(2) - 143.
Therefore the value of m = 2.
.
Hope this helps!
siddhartharao77:
:-)
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