Question

solve no 3 question

Answer 1

done


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Answer 2

since , we know tangents drawn from an external point to a circle are equal.

so now

in triangle ABC ,

CE = CF , AF = AD , BE = BD

let AD = AF = a , BD = BE = b ,

CE = CE = c

then ,

AB = a + b = 12 cm ---(1)

BC = b + c = 8 cm ----(2)

AC = a + c = 10 cm ---(3)

on adding eq.(1) , (2) and (3) , we get



2 ( a+ b + c ) = 12 + 8 + 10 = 30

a + b + c = 30 ÷ 2


a+ b + c = 15 cm

since, a + b = 12 cm => c = 15 - 12 = 3cm

put value of 'c' in eq.(3) ,we get

a = 10 - 3 = 7cm


put value of 'a' in (1) , we get


b = 12 - 7 = 5cm


thus ,

AD = a = 7cm , BE = b = 5cm and CF= c = 3cm


Answer: AD = 7cm, BE = 5cm , CF = 3cm