Solve no. 7 and 8 with steps .....
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a^2- b^2 = (a+b) ( a-b)
249+248 ×249-248
497×1.
497
keerthi124:
x^2+y^2= xy
x2+y2-xy=0
x3+y3=x+y×x2-xy+y2
if x+y=0
x3 +y3 =0
the value of x3+y3=0
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Answer is 497 .As you can use property of :a^2-b^2=(a+b)*(a-b).
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