solve:number 4 please
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(t-2)×(t+3)
t*t + (-2*t )+(3*t)+(3*-2)
t^2 - 2t +3t -6
=t^2 +t -6
t*t + (-2*t )+(3*t)+(3*-2)
t^2 - 2t +3t -6
=t^2 +t -6
RahulBanerjee007:
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hey sci10 plz
thank you so much
Answered by
1
t-2×t+3
=tsquare+3t-2t-6
ans=t square+t-6
=tsquare+3t-2t-6
ans=t square+t-6
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