Question

solve numerical of pressure plz

Answer 1

Answer:

solution]

solution: Force or thrust here =F= 4 N. Area A = 0.003 m^2. Pressure exerted = P = F/A = 4/0.003 Pa = 1333.33 Pa.

solution: Force or thrust here =F=600 N. Area A = 0.012 m^2. Pressure exerted = P = F/A = 600/0.012 Pa = 5 x 10^4 Pa.

solution: Force or thrust here =F=250 N. Pressure exerted = P = 25,000 Pa.