Question

solve numerical plzzzz​

Answer 1

GIVEN :

• mass of the body = 500 g = 0.5 kg
• time taken = 10 sec
• Force = 1/100 N
• initial velocity = 0 (rest )

SOLUTION:

Force is given by the formula ,

$F = m \times a$

$a = \frac{F}{m}$

$a = \frac{0.01}{0.5}$

$\boxed{a = 0.02 \frac{m}{ {s}^{2} } }$

Now in order to find the distance travelled by the block use the second equation of motion

$s = ut + \frac{1a {t}^{2} }{2}$

here ,

• s = distance travelled
• u = initial velocity
• a = acceleration
• t = time taken

As initial velocity of the body is 0

$s = \frac{1a {t}^{2} }{2}$

$s = \frac{0.02 \times 100}{2}$

$\boxed{s = 1m}$